O-LevelPhysicsThermal Physics5054/22 · May/June 2015 · Q45 Marks
A metal can and a plastic bottle, both containing liquid, are cooled by placing them in a jug of melting ice, as shown in Fig. 4.1. [Figure 4.1] The can and bottle each contain 330 g of the same liquid at 15°C.
- (a)The specific heat capacity of the liquid is 4.2J/(g°C). Calculate the thermal energy released when 330 g of the liquid at 15°C cools to 2°C. energy =[2]
- (b)When water at 0°C is used in the jug, instead of the melting ice, the cooling is slower. Explain why cooling is faster when using melting ice in the jug, rather than water at 0°C.[2]
- (c)The liquid in the metal can cools down faster than the liquid in the plastic bottle. Suggest why this happens.[1]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2015). The mark or mark type is shown in brackets.
- [1] (a) (H=) mcT or 330 × 4.2 × 13
- [1] (a) 18000 J or 18020 J or 18018 J
- [1] (b) ice takes in/needs heat/energy
- • for latent heat
- • to melt/turn to water (at 0°C)/change state
- • to break bonds/for molecules to gain P.E.
- [1] (b) water (in jug initially at 0°C) warms up
- or ice (and melted water in jug)
- • stays at 0°C/stays cold/stays at constant temp.
- • gives larger temperature difference (between liquid and melting ice in jug)
- [1] (c) metal is a good conductor (of heat)
- or metal/can has lower heat capacity
- allow opposite statements for plastic, e.g. plastic is an insulator (of heat),
- penalise wrong statements and Physics, e.g. liquid evaporates from can, metals
- conduct temperature/convect better
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