The apparatus shown in Fig. 1.1 is used to measure the extension of a spring. [Figure 1.1]
- (a)Explain how the mass causes a force on the spring.[1]
- (b)The force on the spring is a vector quantity. State what is meant by a vector quantity.[1]
- (c)(i) 1.State a formula that relates the unstretched length lo of the spring, the stretched length I of the spring and the extension e of the spring.[1]
- (c)(i) 2.A mass produces a force of 9.0N on the spring. Determine the extension of the spring caused by this mass. extension =[1]
- (c)(ii)The limit of proportionality of the spring is reached when the force is 10N. The spring is easier to stretch after the limit of proportionality. On Fig. 1.2, continue the line to suggest how the length changes when the force is greater than 10N.[1]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2015). The mark or mark type is shown in brackets.
- [1] (a) weight (pulls spring down and causes tension)
- or force/pull of gravity
- or mass is in gravitational field
- [1] (b) has a direction
- [1] (c) (i) 1. l = lo + e or lo = l− e or e = l − lo
- [1] (c) (i) 2. 36 cm
- [1] (c) (ii) curve upwards after 10N
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