O-LevelPhysicsElectricity5054/21 · May/June 2015 · Q66 Marks
Fig. 6.1 shows a circuit that contains a resistor connected to a power supply of 6.0V and a lamp L. The resistor has a resistance of 60Ω. The lamp is marked 6.0V, 0.90W. [Figure 6.1]
- (a)(i)the current in the resistor,[2]
- (a)(ii)the current in the power supply.[2]
- (b)(i)In the space below draw a circuit diagram of this new circuit. The power supply, 60Ω resistor and lamp L have been drawn for you.[1]
- (b)(ii)The two lamps are identical. Explain why the second lamp is dimmer than lamp L. A calculation is not required.[1]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2015). The mark or mark type is shown in brackets.
- [1] (I=) V/R or 6/60
- [1] 0.1(0) A
- [1] (I=) P/V or 0.9/6 or 0.15 (A) seen
- [1] 0.25 A
- [1] lamp correctly drawn in series with resistor but not the lamp
- [1] less voltage (across lamp) because some voltage across resistor/shares voltage with resistor or less current because of effect of resistor
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