Fig. 2.1 shows a man of mass 80kg standing in a lift (elevator). [Figure 2.1] The gravitational field strength g is 10N/kg.
- (a)Calculate the weight of the man. weight =[1]
- (b)(i)The lift accelerates upwards uniformly at 0.50m/s2. Calculate: the resultant upward force on the man resultant force =[2]
- (b)(ii)the force exerted on the man by the floor of the lift. force =[1]
- (c)The lift accelerates upwards uniformly from rest for 4.0s and then decelerates uniformly to rest in 4.0 s. The total distance travelled is 8.0 m. On Fig. 2.2, sketch the distance-time graph for this journey. [Figure 2.2][3]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2021). The mark or mark type is shown in brackets.
- [B1] 800 N c.a.o.
- [C1] (F =) ma or 80 × 0.50
- [A1] 40 N
- [B1] 840 N
- [B1] increasing gradient from origin to t = 4.0 s
- [B1] decreasing gradient from end of first curve
- [B1] line horizontal at origin or at t = 8.0 s (and beyond)
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