Fig. 1.1 shows a wooden bench of weight 2000 N. [Figure 1.1]
- (a)Each of the two supports has an area of 0.040m² in contact with the ground. Calculate the pressure on the ground due to the bench. pressure =[2]
- (b)(i)The centre of mass of the bench is 1.1 m from the left-hand end of the bench and 0.24 m from the front. Suggest one reason why the centre of mass is in this position.[2]
- (b)(ii)There is a force exerted vertically downwards from the point P shown in Fig. 1.1. Calculate the maximum force that can be exerted vertically downwards at P without the bench rotating about the point Q shown in Fig. 1.1. maximum force =[3]
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Mark scheme
Marking points from the official mark scheme (Oct/Nov 2021). The mark or mark type is shown in brackets.
- [C1] (p =) F/A or 2000 / (2 × 0.040) or 50 000 (P−a)
- [A1] 25 000 Pa
- [B1] symmetrical left-to-right or symmetrical front-to-back or bench is stable
- [B1] because centre of mass is in middle (horizontally) or centre of mass is within the base
- [C1] (moment =) Fx or Wy or 2000 × (1.1 – 0.25) or 2000 × 0.85
- [C1] clockwise moment = anticlockwise moment or Fx = Wy or Fx = 2000 × (1.1 – 0.25) or Fx = 2000 × 0.85 or (F =)2000 × 0.85 / 0.25
- [A1] 6800 N
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