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O-LevelPhysicsForces5054/21 · Oct/Nov 2020 · Q36 Marks

Fig. 3.1 shows a door and an automatic door-closer viewed from above. [Figure 3.1] When the door opens and closes, the hinge acts as a pivot. A girl opens the door by exerting a force P at point X. Force P is perpendicular to the surface of the door.

  1. (a)(i)Fig. 3.1 shows that point X is a distance of 0.72m along the front of the door from the hinge. The force P is 25 N. Calculate the moment of force P about the hinge.[2]
  2. (a)(ii)The door rotates about the hinge by 90°. The circumference of a circle of radius 0.72 m is 4.5m. Calculate the work done on the door by force P.[2]
  3. (b)As the door opens, there is a force F on the door in the direction shown in Fig. 3.1. Although force F is larger than force P, the door rotates about the hinge. Explain why.[2]

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Mark scheme

Marking points from the official mark scheme (Oct/Nov 2020). The mark or mark type is shown in brackets.

  1. [C1] (Γ=) FXr or 25 × 0.72
  2. [A1] 18 N m
  3. [B1] (WD =) Fx or Fdr/2 or 25 × 4.5/4 or 25 × 1.13
  4. [B1] 28 J
  5. [B1] moment due to force P is greater
  6. [B1] distance of X to hinge is greater than distance from where force F acts

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About this question

Topic
Forces, O-Level Physics (syllabus 5054). Structured question, 6 marks.
Source
O-Level Physics, Oct/Nov 2020 Paper 2 Variant 1, question 3.

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