[Figure 9.1] shows a boiling liquid at its boiling point, trapped in a cylinder by a piston. There is an electric heater in the liquid which is connected to a power supply. The thermal energy produced by the heater gradually turns the boiling liquid into a gas.
- (a)State what is meant by boiling point.[2]
- (b)Explain, in terms of molecules, why it is necessary to supply energy in order to turn a liquid at its boiling point into a gas.[3]
- (c)In order to determine the power of the electric heater, two meters are connected into the circuit. One meter measures the current in the heater and the other meter measures the potential difference (p.d.) across it. On the circuit in Fig. 9.1, draw symbols to show the two meters used and where they are connected.[2]
- (d)(i)The current in the heater is 2.0A and the p.d. across it is 6.0 V. Calculate the power of the heater.[2]
- (d)(ii)Calculate the thermal energy supplied to the liquid by the heater in 1.0 minute.[2]
- (d)(iii)The specific latent heat of vaporisation of the liquid is 9.0 × 10⁵J/kg. Calculate the mass of liquid that vaporises every minute.[2]
- (e)The piston is free to move in the cylinder. As the liquid boils, the piston is pushed upwards in the cylinder at a constant speed. The volume occupied by the gas just above the liquid increases. Discuss whether the upward force on the piston changes as the piston moves upwards at constant speed.[2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2019). The mark or mark type is shown in brackets.
- [B1] temperature
- [B1] at which a liquid becomes a gas / vapour
- [B1] forces (between the molecules of the liquid) / bonds mentioned
- [B1] move molecules apart or overcome forces (between the molecules)
- [B1] work done against forces or gains (molecular) potential energy
- [B1] ammeter symbol in series
- [B1] voltmeter symbol across the heater / power supply
- [C1] (P=) VI or 6.0 × 2.0
- [A1] 12 W
- [C1] (E=) Pt or 12 x 60 or (E =) VIt or 6.0 × 2.0 × 60
- [A1] 720 J
- [C1] (m =) Q/Lᵥ or 720 / (9.0 × 10⁵)
- [A1] 8.0 x 10⁻⁴ kg or 0.80 g
- [B1] (it / upward force) does not change
- [B1] always equal to weight of piston + force due to atmospheric pressure or no resultant force or piston is not accelerating
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