A 4.5V battery is connected in a circuit with an ammeter, a light-dependent resistor (LDR) and a 1800 Ω fixed resistor. [Figure 7.1] is the circuit diagram.
- (a)(i)The resistance of the LDR is 9000 Ω. Calculate the total resistance of the circuit,[2]
- (a)(ii)the reading on the ammeter.[2]
- (b)(i)A very bright lamp is switched on and the light intensity on the LDR increases. State and explain what happens to the current in the LDR,[1]
- (b)(ii)the current in the 1800Ω resistor.[1]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2017). The mark or mark type is shown in brackets.
- [C1] 1/R = 1/R₁ + 1/R₂ or R₁R₂/(R₁ + R₂) or 1/R = 1/1800 + 1/9000 or 9000 × 1800/10 800 or 0.00066667
- [A1] 1500 Ω
- [C1] (I =) V/R or 4.5/1500
- [A1] 0.0030 A or 3.0 × 10⁻³ A or 3.0 mA
- [B1] increases and resistance of LDR decreases
- [B1] does not change and resistance/e.m.f. does not change/not affected by LDR
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →