Fig. 4.1 shows a screwdriver of mass 64g resting in equilibrium on a pivot. [Figure 4.1]
- (a)On Fig. 4.1, mark and label with a C, the centre of mass of the screwdriver.[1]
- (b)(i)The gravitational field strength is 10N/kg. Calculate the weight of the screwdriver. weight = [1]
- (b)(ii)On Fig. 4.1, draw an arrow labelled W to represent the weight of the screwdriver.[1]
- (c)State two conditions that apply when an object is in equilibrium. 1. 2.[2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2015). The mark or mark type is shown in brackets.
- [1] (point) C immediately above tip of pivot (and in middle(vertically) of screwdriver (±1mm))
- [1] 0.64 N
- [1] arrow W vertically downwards through candidate's C or pivot
- [1] no resultant force or upward force = downward force or force left = force right
- [1] no resultant moment (of force) or clockwise moment = anticlockwise moment
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