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O-LevelPhysicsForces5054/21 · Oct/Nov 2015 · Q45 Marks

Fig. 4.1 shows a screwdriver of mass 64g resting in equilibrium on a pivot. [Figure 4.1]

  1. (a)On Fig. 4.1, mark and label with a C, the centre of mass of the screwdriver.[1]
  2. (b)(i)The gravitational field strength is 10N/kg. Calculate the weight of the screwdriver. weight = [1]
  3. (b)(ii)On Fig. 4.1, draw an arrow labelled W to represent the weight of the screwdriver.[1]
  4. (c)State two conditions that apply when an object is in equilibrium. 1. 2.[2]

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Mark scheme

Marking points from the official mark scheme (Oct/Nov 2015). The mark or mark type is shown in brackets.

  1. [1] (point) C immediately above tip of pivot (and in middle(vertically) of screwdriver (±1mm))
  2. [1] 0.64 N
  3. [1] arrow W vertically downwards through candidate's C or pivot
  4. [1] no resultant force or upward force = downward force or force left = force right
  5. [1] no resultant moment (of force) or clockwise moment = anticlockwise moment

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About this question

Topic
Forces, O-Level Physics (syllabus 5054). Structured question, 5 marks.
Source
O-Level Physics, Oct/Nov 2015 Paper 2 Variant 1, question 4.

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