O-LevelPhysicsElectricity5054/22 · Oct/Nov 2014 · Q77 Marks
The circuit of Fig. 7.1 includes an ammeter, a 6.0Ω resistor, a length of metal resistance wire and three 1.5V cells connected in parallel. [Figure 7.1]
- (a)(i)State one advantage of using cells in parallel rather than using a single cell,[1]
- (a)(ii)State the potential difference (p.d.) between points P and Q in the circuit of Fig. 7.1.[1]
- (b)(i)The ammeter in Fig. 7.1 reads 0.075A. Calculate the resistance of the resistance wire.[3]
- (b)(ii)The temperature of the metal resistance wire increases. State and explain the effect of this temperature increase on the ammeter reading.[2]
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Mark scheme
Marking points from the official mark scheme (Oct/Nov 2014). The mark or mark type is shown in brackets.
- [1] lasts longer or one cell can be replaced without switching off the circuit or less (internal) resistance or if one fails the others still work
- [1] 1.5V
- [1] (R_total = )V/I or 1.5/0.075 (for total resistance calculation)
- [1] R_wire = R_total - R_resistor = 20 (Ω) - 6.0 (Ω) (for identifying how to get wire resistance)
- [1] 14Ω (for final answer)
- [1] decreases
- [1] resistance of wire increases
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