O-LevelPhysicsForces5054/11 · Oct/Nov 2012 · Q71 Mark

Masses X and Y are placed on opposite sides of the centre of a uniform metre rule, which is pivoted at its centre. Which combination of masses and distances balances the rule?

This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.

Amass/g X: 200, Y: 200, distance/cm p: 5, s: 10

Bmass/g X: 200, Y: 300, distance/cm p: 10, s: 15

Cmass/g X: 400, Y: 300, distance/cm p: 12, s: 16

Dmass/g X: 500, Y: 200, distance/cm p: 15, s: 30

✓ Correct answer

C: mass/g X: 400, Y: 300, distance/cm p: 12, s: 16

Oracle Prep sorts past-paper questions by topic, so you can drill Forces and see which topics are most likely to come up next.

Questions and mark schemes are from past examination papers and remain the copyright of the exam board. How Oracle Prep builds its content