A student investigates the resistance of a lamp.
- (a)Fig. 1.1 shows the circuit used.
- (a)(i)The student closes the switch. The readings of current I₁ and potential difference V₁ are shown in Fig. 1.2. Record the readings shown. IL = VL =[2]
- (a)(ii)The student opens the switch. Suggest why the switch is opened after the readings are recorded.[1]
- (a)(iii)Use the equation R=V/I to calculate the resistance R₁ of the lamp. Give your answer to 2 significant figures. RL=[2]
- (b)(i)The student: • rearranges the circuit and connects a 10Ω resistor in series with the lamp • connects the voltmeter to measure the potential difference across the resistor and lamp combination. In the space below, draw the new circuit with the resistor added.[1]
- (b)(ii)The reading on the voltmeter does not change. Fig. 1.3 shows the new current reading on the ammeter. This is current Ic. Record Ic. Ic = Use the equation in (a)(iii) to find the resistance Rĉ of the lamp and the resistor connected in series. Rc =[2]
- (b)(iii)Theory states that the value of R₁ in the new circuit is given by: RL = RC-10 Calculate the resistance R₁ of the lamp. RL=[1]
- (b)(iv)State how the brightness of the lamp changes in the new circuit compared to the circuit shown in Fig. 1.1, and explain why. change in brightness of lamp explanation[2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →