Fig. 6.1 shows an electric circuit containing a filament lamp, a resistor R, a 12V battery and five meters. [Figure 6.1]
- (a)(i)The reading on ammeter A₁ is 0.25A. The reading on voltmeter V₁ is 3.0V. Determine the readings on the other meters. reading on ammeter A₂ = ................................................. A reading on ammeter A₃ = ................................................. A reading on voltmeter V₂ = ................................................. V[2]
- (a)(ii)Calculate the resistance of resistor R. resistance of resistor R = ................................................. Ω[2]
- (a)(iii)The resistor obeys Ohm's law. State Ohm's law.[2]
- (b)Fig. 6.2 shows the current-voltage graph for the filament lamp. [Figure 6.2] The battery in Fig. 6.1 is replaced with a different battery which has a different e.m.f. (electromotive force). The voltage across the lamp increases to 6.0V. Use data from the graph to determine the e.m.f. of the second battery. Show your working. e.m.f. = ................................................. V[3]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2023). The mark or mark type is shown in brackets.
- [B1] ammeter A₂ and A₃ both 0.25 (A)
- [B1] voltmeter V₂ 9(.0 V)
- [C1] (R =) V/I in any form
- [A1] 36 (Ω)
- [B1] current is (directly) proportional to voltage / potential difference
- [B1] provided the temperature is constant
- [B1] 0.35 (A) seen
- [B1] voltage (across R) 0.35 × 36 or 12.6 (V) seen
- [B1] 19 V
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