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O-LevelPhysicsNuclear Physics5054/21 · May/June 2023 · Q108 Marks

Carbon-14 is an isotope of carbon. It undergoes radioactive decay with a half-life of 6000 years. The age of a sample of wood is found using the carbon-14 that it contains.

  1. (a)Describe what happens during radioactive decay.[2]
  2. (b)The count rate of the carbon-14 in the sample of wood is initially 1600 counts/minute. On Fig. 10.1 draw a graph to show how the count rate will vary over the next 24000 years. The initial count rate is already marked with an x. [Figure 10.1][2]
  3. (c)Name the apparatus used to measure the radiation from the sample of wood and describe how it is used to measure the count rate.[2]
  4. (d)Describe how the count rate from a sample of wood is used to find its age.[2]

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Mark scheme

Marking points from the official mark scheme (May/June 2023). The mark or mark type is shown in brackets.

  1. [B1] emission from the nucleus
  2. [B1] of an alpha particle or beta particle or gamma (radiation)
  3. [C1] at least three points plotted at (6000, 800), (12000, 400), (18000, 200) and (24 000, 100)
  4. [A1] all points correct and smooth curve drawn
  5. [B1] GM (tube and) counter (and timer)
  6. [B1] measure number of counts in a specified time (e.g. 1 min) or subtract background count or tube connected to ratemeter
  7. [B1] measure count rate of similar (mass) sample of living / fresh wood
  8. [B1] use the graph to find time or description of use of half-life to find age

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About this question

Topic
Nuclear Physics, O-Level Physics (syllabus 5054). Structured question, 8 marks.
Source
O-Level Physics, May/June 2023 Paper 2 Variant 1, question 10.

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