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O-LevelMathematicsMensuration4024/23 · May/June 2025 · Q1810 Marks

The diagram shows a cuboid. The length of the cuboid is x cm. The height of the cuboid is 3 times its length. The width of the cuboid is 4 cm less than its length.

  1. (a)Write down expressions, in terms of x, for the height of the cuboid and the width of the cuboid.[2]
  2. (b)The surface area of the cuboid is 200cm². Form an equation in x and show that it simplifies to 7x²-16x-100 = 0.[4]
  3. (c)Solve the equation 7x²-16x-100 = 0. You must show all your working and give your answers correct to 2 decimal places.[3]
  4. (d)Find the height of the cuboid.[1]

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Mark scheme

Marking points from the official mark scheme (May/June 2025). The mark or mark type is shown in brackets.

  1. [2] [height = ] 3x
  2. [width = ] x - 4
  3. B1 for each
  4. [4] 2x(3x) + 2x(x – 4) + 2(3x)(x – 4)
  5. Or 2 (x(3x) + x(x – 4) + 3x(x – 4))
  6. M2 FT their algebraic expressions in x for height and width
  7. B1FT for two different areas seen e.g. two of x(3x), x(x – 4), (3x)(x – 4) or better
  8. M1dep Dep on M2 earned
  9. Set equal to 200 and expansion of their algebraic brackets
  10. A1 with no errors or omissions
  11. [3] 5.09 and -2.81
  12. B2 for √(-16)²-4×7×-100 or for -(-16)±√k / 2x7 OR 8/7 ± √(100/7 + (8/7)²) oe
  13. B1 for each
  14. [1] 15.27 to 15.3
  15. FT 3 × their positive root from (c)

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About this question

Topic
Mensuration, O-Level Mathematics (syllabus 4024). Structured question, 10 marks.
Source
O-Level Mathematics, May/June 2025 Paper 2 Variant 3, question 18.

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