ABCD and EFGD are rectangles. [Figure showing two rectangles, EFGD enclosing ABCD, with dimensions labelled as x, 2x-3, x+3, x-2]
- (a)(i)Show that CD = x-1.[1]
- (a)(ii)The area of rectangle ABCD is 1/5 of the area of rectangle EFGD. Form an equation in x and show that it simplifies to x²-6x+3 = 0.[3]
- (b)(i)Use the quadratic formula to solve the equation x²-6x+3 = 0. You must show all your working and give your answers correct to 2 decimal places.[3]
- (b)(ii)Calculate the shaded area.[2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2025). The mark or mark type is shown in brackets.
- [1] With no error seen leading to x-1
- [3] M1 e.g. 5 × 3(x – 1) = (2x – 3)(x + 3) oe B1 2x²-3x+6x-9 or better A1 With no errors or omissions at any stage in the working
- [3] B2 [--]6±√(-6)²-4×1×3 / 2×1 oe or B1 for (-6)²-4×1×3 or better or for [--]6+√k / 2 oe or [--]6-√k / 2 oe B1 5.45 and 0.55
- [2] M1 for substituting their x value into correct area formula, where x > 2 e.g. (2x-3)(x+3)-3(x-1) oe
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →