O-LevelMathematicsVectors and transformations4024/13 · May/June 2025 · Q245 Marks
The diagram shows the quadrilateral OACB. OA = a and OB = b. OB is parallel to AC and AC = 2OB. [Figure 24.1]
- (a)Find, in its simplest form, in terms of a and b
- (a)(i)AB[1]
- (a)(ii)OC.[1]
- (b)X is the point on OC such that OX : XC = 4 : 1. Find BX. Give your answer in its simplest form in terms of a and b.[3]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2025). The mark or mark type is shown in brackets.
- [1] (a)(i) b - a final answer
- [1] (a)(ii) a + 2b final answer
- [3] (b) (4/5)a + (3/5)b final answer
- M2 for -b + (4/5)their(a+2b) oe
- or M1 for correct route for BX or OX = (4/5)OC or OX = (4/5)their(a)(ii) oe
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