The diagram shows the positions of three ports A, B and C. The bearing of port B from port A is 107°. The bearing of port C from port A is 192°. AB = 176 km and AC = 132 km.
- (a)Find the bearing of A from B.[1]
- (b)Calculate BC. BC = km[4]
- (c)Boat B leaves port B at 10.00 am. It sails directly to port A at an average speed of 48 km/h. Boat C leaves port C at 10.15 am. It sails directly to port A and arrives there 7 minutes before boat B. Find the average speed of boat C in km/h. km/h[5]
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Mark scheme
Marking points from the official mark scheme (May/June 2024). The mark or mark type is shown in brackets.
- [1] 287
- [4] 211 or 210.5 to 210.6
- [4] B1 for angle CAB = 85 soi
- [4] B2 for 44350.[...]
- [4] or M2 for √(176² + 132² - 2×176×132cos(their85)) oe
- [4] or M1 for 176² + 132² - 2×176×132cos(their85) oe
- [5] 40
- [5] If hours and minutes used, apply first scheme
- [5] M2 for (176/48) × 60 oe soi
- [5] or M1 for 176/48 oe
- [5] OR
- [5] M2 for 176/48 and 7/60 or and 15/60 oe soi
- [5] or M1 for 176/48 oe
- [5] AND
- [5] M2 for 132/((their 220)-15-7)[×60] oe
- [5] or M1 for 1.33pm oe
- [5] or (their 220) – 15 – 7 oe
- [5] or (132/(their 220+k)) × 60 oe
- [5] OR
- [5] M2 for 132/((their (176/48) - 15/60) - 7/60) oe
- [5] or M1 for (their (176/48) - 15/60) oe
- [5] or (132/(their (176/48)+k)) oe
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