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O-LevelMathematicsAlgebra and graphs4024/22 · May/June 2023 · Q213 Marks

One chocolate bar costs p cents and one packet of sweets costs 75 cents. Tanish pays $9.10 for 5 chocolate bars and 8 packets of sweets. Form an equation and solve it to find the value of p. Show your working.

  1. (a)One chocolate bar costs p cents and one packet of sweets costs 75 cents. Tanish pays $9.10 for 5 chocolate bars and 8 packets of sweets. Form an equation and solve it to find the value of p. Show your working.[3]
  2. (b)Factorise 6ac – 27c.[2]
  3. (c)Write 3m²n/10 - 5n/9m as a single fraction in its simplest form.[2]
  4. (d)Rearrange the formula y = 3x²/5 to make x the subject.[2]
  5. (e)A group of k numbers has a mean of 56.8 . The number 52 is added to the group. The new mean is 56.5. Find the value of k.[4]

Mark scheme

Marking points from the official mark scheme (May/June 2023). The mark or mark type is shown in brackets.

  1. [B1] 5p+8×75=910 or 5p=910-8×75 or 5p/100+8×75/100=9.1[0] or 5P/100=9.1[0]-8×75/100
  2. [B2] M1 for correctly rearranging their equation to p = ...
  3. 62
  4. After 0 scored, SC1 for answer [$]0.62
  5. [2] B1 for 3c(2a – 9) seen and spoilt or final answer 3(2ac – 9c) or c(6a – 27)
  6. 3c(2a-9) or -3c(9-2a) final answer
  7. [2] B1 for m²n²/6 seen and spoilt or answer with two of 1/6, m and n²
  8. mn²/6 final answer
  9. [2] B1 for [±]√(5y/3) seen and spoilt or x² = 5y/3
  10. [±]√(5y/3) oe final answer
  11. [4] B3 for 56.8k – 56.5k = 56.5 – 52 or better
  12. or B2 for (56.8k + 52) / (k + 1) = 56.5 oe
  13. or B1 for 56.8k or 56.5(k + 1) oe seen
  14. Alternative method
  15. B3 for 56.8x - 56.5x = (56.5 – 52)×56.8 or better
  16. or B2 for x/56.8 or (x-56.5+52)/56.5 oe
  17. or B1 for k = x/56.8 or (x±52)/(k+1) = 56.5 oe seen
  18. 15

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About this question

Topic
Algebra and graphs, O-Level Mathematics (syllabus 4024). Structured question, 13 marks.
Source
O-Level Mathematics, May/June 2023 Paper 2 Variant 2, question 2.

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