(a) Apples cost $x per kilogram and oranges cost $y per kilogram. The total cost of 5 kg of apples and 10kg of oranges is $40. (b) Solve -8 < 4(x-3) < 7. (c) Solve 4/(x-1) + 2/(2x+3) = 1. Show all your working and give your answers correct to 2 decimal places.
- (a)(i)Show that x+2y = 8.[1]
- (a)(ii)The total cost of 4kg of apples and 3 kg of oranges is $19. Use simultaneous equations to find the cost of 1 kilogram of apples and of 1 kilogram of oranges. Show your working.[4]
- (b)Solve -8 < 4(x-3) < 7.[3]
- (c)Solve 4/(x-1) + 2/(2x+3) = 1. Show all your working and give your answers correct to 2 decimal places.[6]
Mark scheme
Marking points from the official mark scheme (May/June 2022). The mark or mark type is shown in brackets.
- [1] 5x + 10y = 40 leading to x + 2y = 8
- [4] Apples $2.80, Oranges $2.60
- B1 4x + 3y = 19
- M1 Correct method to eliminate one variable
- A2 A1 for either x = 2.8[0] or y = 2.6[0] nfww
- After A0 scored, SC1 for a pair of values that satisfy either correct equation or for correct answers with no working or with incorrect
- [3] 1 < x < 4 3/4 oe final answer
- B2 for 1 < x or x < 4 3/4 oe
- or M1 for -8/4 [...] x - 3 [...] 7/4 or better or -8 + 12 [...] 4x [...] 7 + 12 or better
- [6] 5.65 and -1.15
- B3 2x²-9x-13 [= 0]
- B2 for (4(2x+3)+2(x-1)) / ((2x+3)(x-1)) [=1] or better
- or B1 for 4(2x + 3) + 2(x – 1) oe or for (2x + 3)(x – 1) or better
- B2FT their 3-term quadratic
- B1FT for √(-9)² - 4×2×-13 oe or for -(-9)±√(their discriminant) / (2×2)
- or for (x + (-9)/(2×2))² + ((-13)/(2×2)) - ((-9)/(2×2))²
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