O-LevelMathematicsAlgebra and graphs4024/22 · May/June 2020 · Q26 Marks
The length of a rectangle is 6cm more than its width, wcm. The perimeter of the rectangle is 37 cm. Form an equation in w and solve it to find the width of the rectangle.
- (a)The length of a rectangle is 6cm more than its width, wcm. The perimeter of the rectangle is 37 cm. Form an equation in w and solve it to find the width of the rectangle.[3]
- (b)[Figure 2.1] A rectangle 20 cm by 8 cm is cut from a rectangle 28 cm by 15cm. Each measurement is given correct to the nearest centimetre. Calculate the upper bound for the area of the shaded region.[3]
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Mark scheme
Marking points from the official mark scheme (May/June 2020). The mark or mark type is shown in brackets.
- [3] (a) w+6+w+w+6+w=37 oe
- [3] M2 M1 for length = w + 6
- [3] B1 6.25
- [3] (b) 295.5
- [3] B1 for two of 28.5, 15.5, 19.5, 7.5
- [3] M1 for their (28.5 × 15.5) – (19.5×7.5)
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