The diagram shows the positions of two ports, A and B, and a lighthouse L. The bearing of B from L is 062°. AB = 13 km, BL = 14km and AL = 8km.
- (a)Calculate the bearing of A from L.[4]
- (b)A boat is located at C. C is 11 km from B and BCA = 90°. The boat travels to port A in a straight line. Find the distance the boat travels.[2]
- (c)The boat then travels in a straight line from port A to port B. It travels at an average speed of 3.75 km/h. Calculate the time taken for the boat to travel from port A to port B. Give your answer in hours and minutes.[2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2019). The mark or mark type is shown in brackets.
- [4] 128[.0]° or 128.03° to 128.04° B3 for 66[.0] or 66.03 to 66.04 or M2 for [cos L] = (14²+8²-13²)/(2×14×8) or M1 for 13² = 14² + 8² – 2 × 14 × 8 × cosL After 0 scored, SC1 for 62 + their BLA
- [2] 6.93 or 6.92 M1 for √13² – 11² isw
- [2] 3 hours 28 minutes M1 for 13/3.75
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →