O-LevelMathematicsAlgebra and graphs4024/21 · May/June 2019 · Q67 Marks
Solve the inequality 10 < 3(x+1) ≤ 24.
- (a)(i)Solve the inequality 10 < 3(x+1) ≤ 24.[3]
- (a)(ii)State the number of integers, x, satisfying 10 < 3(x+1) ≤ 24.[1]
- (b)Find the 3 inequalities which define the region shaded in the diagram.[3]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2019). The mark or mark type is shown in brackets.
- [3] 7/3 < x < 7 oe final answer B2 for 7/3 < x < 7 seen or final answer 7/3 < x or final answer x ≤ 7 B1 for either correct inequality seen or M1 for 10/3 [...] x + 1 [...] 24/3 or 10-3 [...] 3x [...] 24 – 3 soi
- [1] 5
- [3] y ≥ 0 x > y oe 2x + y ≤ 6 oe B1 for each inequality If 0 scored, SC1 for 3 correct equations soi
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