O-LevelMathematicsAlgebra and graphs4024/21 · May/June 2018 · Q711 Marks
The diagram shows the net of an open box of height 3 cm. The area of the base of the box is 15 cm². The length of the rectangular base is x cm. The total area of the net is A cm².
- (a)Show that A = 15 + 6x + 90/x.[2]
- (b)Graham has one of these open boxes. The total area of the net of his box is 65 cm². Write down an equation in x and solve it to find the length of the base of Graham's box. Give your answer correct to 2 decimal places.[4]
- (c)(i)Complete the table below for A = 15 + 6x + 90/x. x 2 3 4 5 6 7 8 A 72 63 61.5 63 66 69.9[1]
- (c)(ii)Draw the graph of A = 15 + 6x + 90/x for 2 ≤ x ≤ 8.[2]
- (c)(iii)Delilah has one of these open boxes. The area of the net of her box is 68 cm². Use your graph to find the length and width of Delilah's box.[2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2018). The mark or mark type is shown in brackets.
- [2] 15+ [2x] 3x + [2x] (15/x * 3)
- [2] M1
- [2] Leading to 15+6x+90/x without error
- [2] A1
- [4] 5.70 or 2.63
- [4] and 6x² – 50x + 90 [= 0] seen
- [4] B1 for 6x² - 50x + 90 [= 0] oe
- [4] AND
- [4] B2FT for (-(-50) ± √((-50)² - 4×6×90))/(2×6)
- [4] or B1FT for √((-50)² - 4×6×90)
- [4] or (-(-50) ± √r)/(2×6)
- [4] After 0, SC2 for 5.70 or 2.63
- [1] 74.25
- [2] Correct smooth curve
- [2] B1FT for at least 5 points correctly plotted
- [2] 6.5 to 6.6
- [2] 2.3 to 2.4
- [2] FT their graph
- [2] B1FT for either correct
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