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O-LevelMathematicsAlgebra and graphs4024/21 · May/June 2018 · Q711 Marks

The diagram shows the net of an open box of height 3 cm. The area of the base of the box is 15 cm². The length of the rectangular base is x cm. The total area of the net is A cm².

  1. (a)Show that A = 15 + 6x + 90/x.[2]
  2. (b)Graham has one of these open boxes. The total area of the net of his box is 65 cm². Write down an equation in x and solve it to find the length of the base of Graham's box. Give your answer correct to 2 decimal places.[4]
  3. (c)(i)Complete the table below for A = 15 + 6x + 90/x. x 2 3 4 5 6 7 8 A 72 63 61.5 63 66 69.9[1]
  4. (c)(ii)Draw the graph of A = 15 + 6x + 90/x for 2 ≤ x ≤ 8.[2]
  5. (c)(iii)Delilah has one of these open boxes. The area of the net of her box is 68 cm². Use your graph to find the length and width of Delilah's box.[2]

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Mark scheme

Marking points from the official mark scheme (May/June 2018). The mark or mark type is shown in brackets.

  1. [2] 15+ [2x] 3x + [2x] (15/x * 3)
  2. [2] M1
  3. [2] Leading to 15+6x+90/x without error
  4. [2] A1
  5. [4] 5.70 or 2.63
  6. [4] and 6x² – 50x + 90 [= 0] seen
  7. [4] B1 for 6x² - 50x + 90 [= 0] oe
  8. [4] AND
  9. [4] B2FT for (-(-50) ± √((-50)² - 4×6×90))/(2×6)
  10. [4] or B1FT for √((-50)² - 4×6×90)
  11. [4] or (-(-50) ± √r)/(2×6)
  12. [4] After 0, SC2 for 5.70 or 2.63
  13. [1] 74.25
  14. [2] Correct smooth curve
  15. [2] B1FT for at least 5 points correctly plotted
  16. [2] 6.5 to 6.6
  17. [2] 2.3 to 2.4
  18. [2] FT their graph
  19. [2] B1FT for either correct

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About this question

Topic
Algebra and graphs, O-Level Mathematics (syllabus 4024). Structured question, 11 marks.
Source
O-Level Mathematics, May/June 2018 Paper 2 Variant 1, question 7.

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