In the diagram, ACD and ECD are triangles with CD = DE. AD and EC intersect at F. B is the point on AC such that BF is parallel to CD. BÂF = 26°, BFC = 38° and CFD = 110°. Find [Figure: Geometric diagram with triangles ACD and ECD, intersecting lines AD and EC, point B on AC, and angles BÂF=26°, BFC=38°, CFD=110°]
- (a)FĈD,[1]
- (b)EḊC,[1]
- (c)AḄF,[1]
- (d)BĈF.[1]
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