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O-LevelMathematicsAlgebra and graphs4024/21 · May/June 2017 · Q512 Marks

The table below is for y = x³ - 3x - 1 . X -3 -2 -1 0 1 2 3 y -19 -3 1 -1 -3 1 [Figure: Graph grid provided for plotting]

  1. (a)Complete the table.[1]
  2. (b)On the grid, draw the graph of y = x³ - 3x - 1 .[3]
  3. (c)Use your graph to solve x³ - 3x - 1 = 0 .[2]
  4. (d)Use your graph to estimate the gradient of the curve when x = -1.5 .[2]
  5. (e)(i)On the grid draw the graph of y = 4x + 3.[1]
  6. (e)(ii)The line y = 4x +3 and the curve y = x³ - 3x - 1 can be used to solve the equation x³ = ax + b . Find the values of a and b.[2]
  7. (e)(iii)Use your graph to find one of the negative solutions of x³ = ax + b .[1]

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Mark scheme

Marking points from the official mark scheme (May/June 2017). The mark or mark type is shown in brackets.

  1. [1] 17
  2. [3] Smooth curve through 7 correct points
  3. [1] B2 for at least 5 ft plots correct
  4. [1] B1 for at least 4 ft plots correct
  5. [2] -1.7 to -1.4, –0.5 to –0.2, 1.7 to 2.0
  6. [1] B1 for 2 correct
  7. [2] 3 to 5 with tangent drawn
  8. [1] B1 for ruled solid tangent drawn
  9. [1] Correct ruled line drawn
  10. [2] a = 7, b = 4
  11. [1] B1 for one correct or a = 6.8 to 7.2 and b = 3.8 to 4.2
  12. [1] -2.4 to -2.1 or -0.7 to -0.5
  13. [1] FT

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About this question

Topic
Algebra and graphs, O-Level Mathematics (syllabus 4024). Structured question, 12 marks.
Source
O-Level Mathematics, May/June 2017 Paper 2 Variant 1, question 5.

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