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O-LevelMathematicsVectors and transformations4024/21 · May/June 2017 · Q46 Marks

A = (2 0 \ 4 -1) B = (2 -1 \ 6 -1)

  1. (a)(i)Calculate BA,[2]
  2. (a)(ii)B⁻¹.[2]
  3. (b)Given that A + 2C = 3B, find C.[2]

Mark scheme

Marking points from the official mark scheme (May/June 2017). The mark or mark type is shown in brackets.

  1. [2] (0 1 \ 8 1)
  2. [1] B1 for (0 1 \ 8 1) or 2 elements correct in a 2 × 2 matrix with brackets
  3. [2] 1/(-1) ( -1 1 \ -6 2 ) oe isw
  4. [1] B1 for for determinant = 4 soi or k(-1 1 \ -6 2)
  5. [2] 1/2 (4 -3 \ 14 -2) or (2 -1.5 \ 7 -1) oe
  6. [1] B1 for 2C = 3B – A or –2C = A – 3B soi or (4 -3 \ 14 -2)
  7. [1] M1 for 1/2 ((2 0 \ 4 -1) + 2C = 3 (2 -1 \ 6 -1))

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About this question

Topic
Vectors and transformations, O-Level Mathematics (syllabus 4024). Structured question, 6 marks.
Source
O-Level Mathematics, May/June 2017 Paper 2 Variant 1, question 4.

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