The diagram shows a vertical wind turbine with blades 30m long. The blades are stationary with the point A being the maximum distance possible from the horizontal ground. The point B is such that the angle of elevation of A from B is 34° and the angle of elevation of the centre of the blades, C, from B is 25°. Calculate the distance AB. [Figure 9.1]
- (a)The diagram shows a vertical wind turbine with blades 30m long. The blades are stationary with the point A being the maximum distance possible from the horizontal ground. The point B is such that the angle of elevation of A from B is 34° and the angle of elevation of the centre of the blades, C, from B is 25°. Calculate the distance AB. [Figure 9.1][3]
- (b)A different wind turbine, shown in the diagram on the next page, has the centre of its blades, F, 75 m from the base of the turbine, D. Point E is on sloping ground, 180m from F and 130m from D. Calculate the angle of depression of E from F. [Figure 9.2][4]
- (c)(i)P is the point on a blade which is furthest from the centre of the blades. Each blade is 30m long. Calculate the distance travelled by P as the blade completes one revolution.[1]
- (c)(ii)The blade completes 15 revolutions per minute. Calculate the speed of P, giving your answer in kilometres per hour.[2]
- (c)(iii)A point Q lies on the straight line between P and the centre of the blades. Q travels 90m as the blade completes one revolution. Calculate PQ.[2]
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Mark scheme
Marking points from the official mark scheme (May/June 2016). The mark or mark type is shown in brackets.
- [3] (a) 173.8 to 174m
- [3] (a) B1 for 9 and 115 soi
- [3] (a) M1 for AB/sin 115 = 30/sin 9 or better
- [4] (b) 51.4 to 51.5
- [4] (b) B3 for 38.5 to 38.6 or
- [4] (b) M2 for cos DFE = (75² + 180² - 130²)/(2×75×180) or
- [4] (b) M1 for 130² = 75² + 180² – 2×75×180 cos F
- [1] (c)(i) 188 to 189
- [2] (c)(ii) 169 to 170.2 km/h
- [2] (c)(ii) M1 for 15 × their 188 seen
- [2] (c)(iii) 15.67 to 16.0
- [2] (c)(iii) M1 for 90/(2π) (= 14.3)
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