O-LevelMathematicsVectors and transformations4024/22 · May/June 2016 · Q26 Marks
JK = (2; 5), KL = (4; -2), LM = (-1; 3) Find JM.
- (a)(i)JK = (2; 5), KL = (4; -2), LM = (-1; 3) Find JM.[1]
- (a)(ii)Calculate |KL|.[2]
- (b)(i)(a)In the diagram, OA = a and OB = b. C is the point such that OAC is a straight line and AC = 2OA. D is the midpoint of OB. E is the point such that EC = OD. Express, as simply as possible, in terms of a and b, AD,[1]
- (b)(i)(b)EB.[1]
- (b)(ii)Find |EB| : |AD|.[1]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2016). The mark or mark type is shown in brackets.
- [1] (a)(i) (5; 6)
- [2] (a)(ii) 4.47 – 4.473 or 4.5 or √20 or 2√5
- [2] (a)(ii) M1 for √((±4)² + (+2)²)
- [1] (b)(i)(a) ½ b – a or ½ (b – 2a) or equivalent two term answers final answer
- [1] (b)(i)(b) 3/2 b – 3a or 3/2 (b – a) or (3b-6a)/2 or equivalent two term answers final answer
- [1] (b)(ii) 3 : 1 cao
- [1] (b)(ii) Dependent on correct (b)(i)(a) and (b)(i)(b)
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