[Figure ABCD] In trapezium ABCD, AB is parallel to DC. DB and AC are straight lines. Explain why the area of triangle ACB = the area of triangle ADB.

1. (a)(i)[Figure ABCD] In trapezium ABCD, AB is parallel to DC. DB and AC are straight lines. Explain why the area of triangle ACB = the area of triangle ADB.[1]
2. (a)(ii)(a)[Figure EHGK] The diagram shows the quadrilateral EHGK. HF is parallel to GK and EFK is a straight line. Name a triangle equal in area to triangle HFK.[1]
3. (a)(ii)(b)Hence show that the area of triangle HEK = the area of quadrilateral HEFG.[1]
4. (b)[Figure PMRLSQ] Two circles intersect at L and M. R and P are on the circumference of one circle. S and Q are on the circumference of the other circle. PLQ and RLS are straight lines. PÎR = x° and MLQ = y°.
5. (b)(i)Complete the proof that SMQ = x°. Statement: x° = PÎR = SLQ SLQ = SMQ = x° Reason:[2]
6. (b)(ii)Prove that PRM = y°. Statement: Reason:[2]
7. (b)(iii)Complete the following statement, giving your reasons. The triangles PRM and QSM are Reasons[3]

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