O-LevelMathematicsAlgebra and graphs4024/22 · Oct/Nov 2024 · Q713 Marks
Solve. 4x+7 = 16
- (a)Solve. 4x+7 = 16[2]
- (b)Solve. 5(4-y) = 30[2]
- (c)Write down all the integers that satisfy this inequality. -3/2 ≤ x < 3[2]
- (d)Rearrange the formula y = (4y-x) / 3x to make x the subject.[3]
- (e)Simplify (12x²-3y²) / (2x²+8x-xy-4y) .[4]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2024). The mark or mark type is shown in brackets.
- [2] x = 9/4 oe
- [M1] for 4x = 16 - 7 or x = 7/4 + 16/4
- [2] y = -2
- [M1] for 4 - y = 6 or 20 – 5y = 30
- [2] -1, 0, 1, 2 final answer
- [B1] for three out of four correct with no extras or four correct with one extra
- [3] x = 4y / (3y+1) final answer
- [M1] for elimination of fraction
- [M1] for isolation of terms in x, FT their first step
- [M1] for factorising and completing to x =, FT their second step
- [Max 2 marks] if final answer not correct
- [4] 3(2x+y) / (x+4) or (6x+3y) / (x+4) final answer
- [B1] for 3(2x + y)(2x - y) or (6x + 3y)(2x – y) or (6x – 3y)(2x + y) seen
- [B2] for (2x - y)(x + 4) seen
- [B1] for one correct partial factorisation seen
- [SC1] if 0 scored, for 3(4x² - y²) seen
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