O-LevelMathematicsGeometry4024/21 · Oct/Nov 2024 · Q88 Marks
ABCD is a field. AB = 320 m, BC = 250m, CD = 132m and AD = 365 m. Angle BCD = 90°. [Figure showing a quadrilateral ABCD with a North line at A]
- (a)Ray walks from A to B at an average speed of 1.6 m/s. He then runs from B to C at an average speed of 2.8 m/s. Calculate Ray's average speed from A to B to C.[3]
- (b)The bearing of D from A is 243°. Calculate the bearing of B from A.[5]
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Mark scheme
Marking points from the official mark scheme (Oct/Nov 2024). The mark or mark type is shown in brackets.
- [3] M2 for (320+250) / (320/1.6 + 250/2.8)
- [3] or M1 for 320/1.6 + 250/2.8
- [5] B4 for 48.19 to 48.3
- [5] OR M1 for [BD²]=1322 + 2502 oe
- [5] M2 for cos[angle] = (365^2 +320^2 – theirBD²) / (2×365×320) or better
- [5] or M1 for theirBD² = 365^2 +320^2-2×365×320cos[angle]
- [5] M1 for bearing = 243 – their BAD
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