y = 4+2x - x²/2
- (a)Complete the table for y = 4+2x-x²/2 x | -2 | -1 | 0 | 1 | 2 | 3 | 4 | 5 | 6 y | | 1.5 | 4 | 5.5 | 6 | 5.5 | 4 | 1.5 |[2]
- (b)Draw the graph of y = 4+2x-x²/2 for -2≤x≤ 6. [Figure showing a coordinate grid][3]
- (c)Find the equation of the line of symmetry of the graph of y=4+2x-x²/2.[1]
- (d)On the grid, draw the line 3y = x+6 for -2≤x≤6.[2]
- (e)Write down the x-coordinates of the points of intersection of the graphs of y = 4+2x-x²/2 and 3y = x+6.[1]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2024). The mark or mark type is shown in brackets.
- [2] B1 for each
- [3] B2FT for 8 or 9 points correctly plotted
- [3] or B1FT for 6 or 7 points correctly plotted
- [1] x = 2
- [2] B1 for short or unruled line
- [2] or for two correct coordinates soi
- [2] or for line with positive gradient passing through (0, 2)
- [2] or for line with gradient 1/3
- [1] STRICT FT x-coordinates of intersection of their ruled line and their curve
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