The scale drawing shows a plot of land, PQRS. The scale is 1 cm to 20 m. [Figure of plot PQRS with North arrow] Scale: 1 cm to 20 m
- (a)A path crosses the land. The path is equidistant from SP and SR. Use a straight edge and compasses only to construct the path.[2]
- (b)(i)Priya walks from point P to the path on a bearing of 104°. Draw a line to represent Priya's walk.[1]
- (b)(ii)Find the actual distance from P to where Priya meets the path.[2]
- (c)A car park is to be built on the plot of land. On the scale drawing the area of the car park will be 2cm². Find the actual area of the car park.[2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2022). The mark or mark type is shown in brackets.
- [2] Acceptable bisector of angle PSR with correct arcs meeting line PQ
- B1 for acceptable bisector of angle PSR with no/incorrect arcs
- [1] Line drawn on bearing 104° from P
- [2] 152 to 160 dep on correct angle bisector and correct bearing drawn
- B1FT for correct measurement of their line from P to their bisector
- or M1 for their distance in cm written and their answer is 20× this value
- [2] 800
- M1 for 1 cm² = 400 m² soi
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