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O-LevelMathematicsAlgebra and graphs4024/21 · May/June 2014 · Q712 Marks

The variables x and y are connected by the equation y = x³/2 - 3x + 1. Some corresponding values of x and y are given in the table below. X | -3 | -2 | -1 | 0 | 1 | 2 | 3 y | | 3 | 3.5| 1 | -1.5| -1|

  1. (a)Complete the table.[2]
  2. (b)On the grid below, plot the points from the table and join them with a smooth curve. [Grid][2]
  3. (c)Use your graph to solve the equation x³/2 - 3x + 1 = 0.[2]
  4. (d)By drawing a tangent, find the gradient of the curve at the point (-2, 3).[2]
  5. (e)(i)The line AB intersects the curve at point P. The coordinates of point A are (0, 5). The coordinates of point B are (2, -3). Find the equation of line AB.[2]
  6. (e)(ii)The x-coordinate of point P is a solution of the equation x³/2 + Cx + D = 0 . Find C and D.[2]

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Mark scheme

Marking points from the official mark scheme (May/June 2014). The mark or mark type is shown in brackets.

  1. [2] B1 for each
  2. [2] P1 for at least 5 correct plots
  3. [2] FT their curve
  4. [2] B1 for 2 correct solutions
  5. [2] M1 On their curve
  6. [2] A1 2 to 3
  7. [2] M1 for y = -4x + k or y = mx + 5 or 4x + 5
  8. [2] M1 for x^3/2 - 3x + 1 = 5 - 4x FT

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About this question

Topic
Algebra and graphs, O-Level Mathematics (syllabus 4024). Structured question, 12 marks.
Source
O-Level Mathematics, May/June 2014 Paper 2 Variant 1, question 7.

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