The variables x and y are connected by the equation y = x³/2 - 3x + 1. Some corresponding values of x and y are given in the table below. X | -3 | -2 | -1 | 0 | 1 | 2 | 3 y | | 3 | 3.5| 1 | -1.5| -1|
- (a)Complete the table.[2]
- (b)On the grid below, plot the points from the table and join them with a smooth curve. [Grid][2]
- (c)Use your graph to solve the equation x³/2 - 3x + 1 = 0.[2]
- (d)By drawing a tangent, find the gradient of the curve at the point (-2, 3).[2]
- (e)(i)The line AB intersects the curve at point P. The coordinates of point A are (0, 5). The coordinates of point B are (2, -3). Find the equation of line AB.[2]
- (e)(ii)The x-coordinate of point P is a solution of the equation x³/2 + Cx + D = 0 . Find C and D.[2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2014). The mark or mark type is shown in brackets.
- [2] B1 for each
- [2] P1 for at least 5 correct plots
- [2] FT their curve
- [2] B1 for 2 correct solutions
- [2] M1 On their curve
- [2] A1 2 to 3
- [2] M1 for y = -4x + k or y = mx + 5 or 4x + 5
- [2] M1 for x^3/2 - 3x + 1 = 5 - 4x FT
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →