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O-LevelMathematicsAlgebra and graphs4024/21 · May/June 2014 · Q57 Marks

(a) Here is part of a number grid. A square can be placed anywhere on the grid outlining four numbers. The numbers in opposite corners of the square are multiplied together and the difference between the products is found. [Table] 9×14-8×15 = 126-120 = 6 (b) Here is part of a different number grid. A cross can be placed anywhere on the grid outlining five numbers. The numbers in the cross are added together. [Table]

  1. (a)(i)The grid is continued downwards. If n represents the number of the top left of the square, complete this square with expressions for the other numbers. n n+1 (blank) (blank)[1]
  2. (a)(ii)Use your answer to part (a)(i) to prove that the difference between the products of the opposite corners is always 6.[2]
  3. (b)(i)Find and simplify an expression, in terms of n, for the sum of the numbers in the cross below. n (empty cross)[2]
  4. (b)(ii)The sum of the numbers in the cross below is 330. Complete the cross with the correct numbers. (empty cross)[2]

Mark scheme

Marking points from the official mark scheme (May/June 2014). The mark or mark type is shown in brackets.

  1. [1] n+6, n+7
  2. [2] M1 for (n + 1)(n + 6) – n(n + 7) or reversed
  3. [2] Or B1 for n² +7n+6
  4. [2] M1 for [n], n + 9, n + 10, n + 11, n + 20 seen
  5. [2] M1 for n = 56
  6. [2] Or for 66 in centre of cross

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About this question

Topic
Algebra and graphs, O-Level Mathematics (syllabus 4024). Structured question, 7 marks.
Source
O-Level Mathematics, May/June 2014 Paper 2 Variant 1, question 5.

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