(a) Here is part of a number grid. A square can be placed anywhere on the grid outlining four numbers. The numbers in opposite corners of the square are multiplied together and the difference between the products is found. [Table] 9×14-8×15 = 126-120 = 6 (b) Here is part of a different number grid. A cross can be placed anywhere on the grid outlining five numbers. The numbers in the cross are added together. [Table]
- (a)(i)The grid is continued downwards. If n represents the number of the top left of the square, complete this square with expressions for the other numbers. n n+1 (blank) (blank)[1]
- (a)(ii)Use your answer to part (a)(i) to prove that the difference between the products of the opposite corners is always 6.[2]
- (b)(i)Find and simplify an expression, in terms of n, for the sum of the numbers in the cross below. n (empty cross)[2]
- (b)(ii)The sum of the numbers in the cross below is 330. Complete the cross with the correct numbers. (empty cross)[2]
Mark scheme
Marking points from the official mark scheme (May/June 2014). The mark or mark type is shown in brackets.
- [1] n+6, n+7
- [2] M1 for (n + 1)(n + 6) – n(n + 7) or reversed
- [2] Or B1 for n² +7n+6
- [2] M1 for [n], n + 9, n + 10, n + 11, n + 20 seen
- [2] M1 for n = 56
- [2] Or for 66 in centre of cross
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →