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O-LevelMathematicsAlgebra and graphs4024/21 · Oct/Nov 2021 · Q912 Marks

9 (a) Solve 3x-8 = 7. x = (b) Solve the inequality 7x < 3(2-x). (c) Solve 3/(x-2) + x/(x+5) = 1. x = (d) Simplify (2x²+3x+4xy +6y) / (2x² + 11x+12)

  1. (a)Solve 3x-8 = 7.[2]
  2. (b)Solve the inequality 7x < 3(2-x).[2]
  3. (c)Solve 3/(x-2) + x/(x+5) = 1.[4]
  4. (d)Simplify (2x²+3x+4xy +6y) / (2x² + 11x+12)[4]

Mark scheme

Marking points from the official mark scheme (Oct/Nov 2021). The mark or mark type is shown in brackets.

  1. [2] (a) x = 5
  2. [2] M1 for 3x = 7 + 8 or better or x = 8/3 + 7/3
  3. [2] (b) x < 3/5 oe final answer
  4. [2] M1 for 7x + 3x [...] 6 or 7/3 x + x [...] 2
  5. [4] (c) 25/2 or 12 1/2 or 12.5
  6. [4] M2 for 3(x + 5) + x(x – 2) = (x – 2)(x + 5) or (3(x+5)+x(x-2)) / ((x+5)(x-2)) = 1
  7. [4] M1 for 3(x + 5) + x(x – 2) or denominator (x – 2)(x + 5) soi
  8. [4] M1 for 3x + 15 + x² – 2x = x² - 2x + 5x – 10
  9. [4] (d) (x + 2y) / (x + 4) final answer
  10. [4] B2 for (x+2y)(2x+3)
  11. [4] B1 for one correct partial factorisation seen AND B1 for (2x+3)(x+4)

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About this question

Topic
Algebra and graphs, O-Level Mathematics (syllabus 4024). Structured question, 12 marks.
Source
O-Level Mathematics, Oct/Nov 2021 Paper 2 Variant 1, question 9.

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