A, B, C and D are points on the circle, centre O. BÂD = 68° and CBO = 52°. Find CÔD.
- (a)A, B, C and D are points on the circle, centre O. BÂD = 68° and CBO = 52°. Find CÔD.[3]
- (b)(i)The cross-section of solid A is the sector of a circle of radius 6 cm and angle 40°. The height of solid A is 5 cm. Calculate the total surface area of solid A.[4]
- (b)(ii)Solid B is mathematically similar to solid A. The ratio volume of solid A : volume of solid B = 27 : 1. Calculate the surface area of solid B.[2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2020). The mark or mark type is shown in brackets.
- [3] 60° nfww B1 for ∠DOB = 136° soi B1 for ∠BCD = 112° soi M1 for ∠CDO = 360 – their 136 – their 112 – 52 Alternative method B1 ∠COB = 76° soi B1 ∠COD = 60° or ∠OCD = 60° soi M1 ZCDO = ∠OCD or ∠CDO = (180 – their 60) ÷ 2 Max 2 marks if answer incorrect
- [4] 106 to 106.1 M1 for [2x] 40/360 ×π×6^2 soi M1 for 40/360 ×2×π×6×5 soi M1 for [2x] 5 × 6 soi
- [2] 11.7 to 11.8 FT their (b)(i) ÷ 9 B1 for 1/√27 or 1/27 soi
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →