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O-LevelMathematicsGeometry4024/21 · Oct/Nov 2019 · Q77 Marks

P, Q, R and S are points on a circle. PXR and QXS are straight lines. [Figure 7 Diagram of circle with inscribed quadrilateral PQRS and intersecting diagonals PXR and QXS]

  1. (a)Show that triangle PQX is similar to triangle SRX. Give a reason for each statement you make.[3]
  2. (b)(i)PX = 8.1 cm, QX = 6.3 cm and SX = 4.5 cm. Calculate RX.[2]
  3. (b)(ii)Find the ratio area of triangle PQX : area of triangle PSX. Give your answer in its simplest form.[2]

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Mark scheme

Marking points from the official mark scheme (Oct/Nov 2019). The mark or mark type is shown in brackets.

  1. [3] ∠PXQ = ∠SXR, vertically opposite B1 for two correct pairs of angles identified ∠QPX= ∠RSX, angles in same B1 for correct reasons for two pairs of angles segment ∠PQX= ∠SRX, angles in same segment Hence similar
  2. [2] 3.5 M1 for RX/4.5 = 6.3/8.1 oe
  3. [2] 7:5 nfww B1 for 6.3 : 4.5 oe nfww

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About this question

Topic
Geometry, O-Level Mathematics (syllabus 4024). Structured question, 7 marks.
Source
O-Level Mathematics, Oct/Nov 2019 Paper 2 Variant 1, question 7.

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