The diagram is the speed-time graph of part of a train's journey. [Figure 24.1] The train slows down uniformly from a speed of 44 m/s to a speed of 20 m/s in a time of 10 seconds. It then continues at a constant speed of 20 m/s.
- (a)Find the deceleration when t = 5.[1]
- (b)Find the speed when t = 5.[1]
- (c)The distance travelled from t = 0 to t = 10 is equal to the distance travelled from t = 10 to t = 10 + k. Find k.[3]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2018). The mark or mark type is shown in brackets.
- 24(a) 2.4 oe final answer [1]
- 24(b) 32 [1]
- 24(c) 16 nfww [3]
- M2 for 1/2 × (44 + 20) × 10 oe = 20k oe
- or M1 for 1/2 × (44 + 20) × 10 oe, or for 20k oe = their distance travelled from t = 0 to t = 10
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