A boat travels from P to Q. At Q, it turns through 90° and travels to R as shown in the diagram. It then returns from R to Q, and then to P, following the same route in reverse. PQ = 6 km and QR = 9 km. The first part of the journey, from P to Q to R, takes 3 hours. The return part of the journey, from R to Q to P, takes 2 hours. [Figure 16.1]
- (a)Calculate the average speed for the whole journey from P to Q to R and back from R to Q to P.[2]
- (b)(i)The bearing of Q from P is 040°. Calculate the bearing of R from Q.[1]
- (b)(ii)Calculate the bearing of P from Q.[1]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2018). The mark or mark type is shown in brackets.
- 16(a) 6 nfww [2]
- M1 for (2 × (6 + 9)) / (time in hours)
- 16(b)(i) 130° [1]
- 16(b)(ii) 220° [1]
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