The points (4, -3) and (0, 5) lie on the line L. Find the equation of line L.
- (a)(i)The points (4, -3) and (0, 5) lie on the line L. Find the equation of line L.[2]
- (a)(ii)The line M is parallel to line L and passes through the point (-2, 3). Find the equation of line M.[2]
- (b)(i)Complete the table.[1]
- (b)(ii)Using a scale of 2cm to 1 unit on both axes, draw a horizontal x-axis for 0 ≤ x ≤ 7 and a vertical y-axis for 0 ≤ y ≤ 4. Draw the graph of y = x + 3/x - 3 for 0.5 ≤ x ≤ 6.[3]
- (b)(iii)By drawing a tangent, estimate the gradient of the curve at (1, 1).[2]
- (b)(iv)Use your graph to solve the equation x + 3/x = 5.[2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2017). The mark or mark type is shown in brackets.
- [2] B1 for y = −2x + c oe or for y = mx + 5 oe
- [2] or M1 for gradient = (5+3) / (0-4) oe
- [2] y = -2x + 5 oe
- [2] B1 for answer y = their (−2)x + k, where k ≠ their 5
- [2] or M1 for 3 = their (−2) × −2 + k_oe
- [2] y = -2x - 1 oе FT their gradient from (a)(i)
- [1] 3.5
- [3] B2FT for 7 or 8 points correctly plotted or B1FT for 5 or 6 points correctly plotted
- [3] Correct smooth curve through 8 correct points
- [2] M1 Clear correct tangent drawn at (1, 1)
- [2] A1 -2.4 to -1.6
- [2] FT reading from their graph at y = 2
- [2] B1 for one correct
- [2] or for y = 2 soi
- [2] 0.6 to 0.8 and 4.2 to 4.4
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