The diagram shows the positions of three towns, A, B and C. B is due north of A and the bearing of C from A is 220°. AB = 25 km and AC = 38km.
- (a)Find the bearing of A from C.[1]
- (b)Show that BC = 59.4km correct to 3 significant figures.[3]
- (c)Calculate the bearing of C from B.[4]
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Mark scheme
Marking points from the official mark scheme (Oct/Nov 2017). The mark or mark type is shown in brackets.
- [1] 040
- [3] M2 or M1 for 25² + 38² – 2 × 25 × 38 × cos(360 - 220)
- [3] BC = √252 +382 - 2×25×38cos(360-220)
- [3] BC = 59.36 to 59.37
- [4] B3 for 24.1 to 24.3[2...]
- [4] M2 for sin B = 38xsin(360-220) / 59.4 or M1 for sin B / 38 = sin(360-220) / 59.4
- [4] and M1 for 180 + their B
- [4] 204.1 to 204.3[2...]
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