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O-LevelMathematicsVectors and transformations4024/12 · Oct/Nov 2017 · Q276 Marks

In the diagram, OP = (-3, 4) and PQ = (2, 0).

  1. (a)Find |OP|+|PQ|.[3]
  2. (b)(i)T is the point where PT = kPQ. (i) Express OT as a column vector in terms of k.[1]
  3. (b)(ii)M is the point such that O, T and M lie on a straight line and OM = (24, 16). Find the value of k.[2]

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Mark scheme

Marking points from the official mark scheme (Oct/Nov 2017). The mark or mark type is shown in brackets.

  1. [3] 27(a) 7
  2. M1 for |OP| = √(-3)² + (4)²
  3. B1 for |PQ| = 2
  4. [1] 27(b)(i) ((-3+2k) (4)) oe
  5. [2] 27(b)(ii) 4½ oe
  6. B1 for expressing OM as a multiple (by 4) of OT
  7. or B1 for T is (6, 4); or for OT = ((6) (4))

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About this question

Topic
Vectors and transformations, O-Level Mathematics (syllabus 4024). Structured question, 6 marks.
Source
O-Level Mathematics, Oct/Nov 2017 Paper 1 Variant 2, question 27.

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