In the diagram, ABC and AFE are straight lines. AB = 6a and BF = 2b. [Figure 24]
- (a)Express AF in terms of a and b.[1]
- (b)(i)AE = 9a + kb. Find k.[1]
- (b)(ii)(a)ED is parallel to BC, CD is parallel to BF and BC = AB. Find, in terms of a and/or b, CD,[1]
- (b)(ii)(b)DE.[1]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2017). The mark or mark type is shown in brackets.
- [1] 6a + 2b oe
- [1] 3
- [1] 3b; or FT kb
- [1] -3a
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →