Six hundred candidates took a mathematics examination which consisted of two papers. Each paper was marked out of 100. The diagram shows, on the same grid, the cumulative frequency curves for Paper 1 and Paper 2. [Figure showing cumulative frequency graph for Paper 1 and Paper 2]
- (a)(i)(a)Use the cumulative frequency curve for Paper 1 to find an estimate of the median,[1]
- (a)(i)(b)the interquartile range,[2]
- (a)(i)(c)the number of candidates who scored more than 45.[1]
- (a)(ii)A candidate scored 60 on Paper 1. Using both graphs, estimate this candidate's mark on Paper 2.[1]
- (a)(iii)State, with a reason, which you think was the more difficult paper.[1]
- (b)(i)Amira has three $1 coins and two 20c coins in her purse. She picks out coins at random, one after the other. The coins are not replaced. The tree diagram shows the possible outcomes and their probabilities when picking out two coins. Find x. [Figure showing a tree diagram with probabilities][1]
- (b)(ii)Find the probability that the total value of the two coins picked out is 40 cents.[1]
- (b)(iii)Find the probability that the total value of the two coins picked out is $1.20 .[2]
- (b)(iv)At a car park, the charge is $1.40 . Amira picks out three coins, one after the other. Find the probability that the total value of the three coins is $1.40 .[2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2016). The mark or mark type is shown in brackets.
- [1] 40 to 41
- [2] 23 to 27
- [1] B1 for 52 ±1 or 27 ±1
- [1] 225 to 245
- [1] 79 to 80
- [1] Paper 1 e.g. Paper 2 has median 54 oe Using (i)(a), (i)(c) or (ii) with numerical justification – accept reasonable attempts to read the graphs correctly.
- [1] 2/4 oe
- [1] 2/20 oe
- [2] 12/20 oe
- [1] B1 for (3/5)*(2/4) or (2/5)*(3/4) seen
- [2] 18/60 oe
- [1] B1 for any correct sequence of three coins, e.g. (3/5)*(2/4)*(1/3) or (2/5)*(3/4)*(1/3) or (2/5)*(1/4)*(3/3)
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