ACB and OCD are straight lines. AC : CB = 1:2. OA = 3a and OB = 6b. [Figure showing a quadrilateral with vectors OA=3a, OB=6b, and points C, D, with lines ACB and OCD]
- (a)(i)Express AB in terms of a and b.[1]
- (a)(ii)Express AC in terms of a and b.[1]
- (a)(iii)BD = 5a-b. Showing your working clearly, find OC : CD .[4]
- (b)(i)Describe fully the single transformation that maps triangle A onto triangle B. [Figure showing triangle A and triangle B on a grid][2]
- (b)(ii)(a)Triangle A is mapped onto triangle C by the shear H in which the y-axis is invariant, and H(2, 1) = (2, 3). On the grid, draw and label triangle C.[2]
- (b)(ii)(b)State the shear factor of H.[1]
- (b)(ii)(c)Find the matrix that represents H.[1]
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Mark scheme
Marking points from the official mark scheme (Oct/Nov 2016). The mark or mark type is shown in brackets.
- [1] 6b – 3a oe isw
- [1ft] 2b – a oe isw
- [4] 2:3 cao NB www
- [1] M1+M1 for two of OC = OA+ AC, CD = CB + BD, OD = OB + BD
- [1] A1 for OC = 2a + 2b ft or CD = 3a + 3b ft or OD = 5a + 5b
- [2] Reflection y = -x oe
- [1] B1 for either
- [2] Triangle C with vertices (2, 3),(2, 2), (5, 5)
- [1] B1 for two vertices correct or
- [1] M1 for a correct construction line involving H(2, 1) or H(2, 0)
- [1] 1
- [1ft] (1 0 / 1 1)
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