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O-LevelMathematicsGeometry4024/22 · Oct/Nov 2016 · Q55 Marks

In the diagram, A and B are the centres of two circles that touch at P. The line ACT touches the small circle at T and intersects the large circle at C. D is the point on AB such that CDA = 90°. [Figure showing two touching circles, line ACT, point D on AB]

  1. (a)Complete the following, to show that triangle ACD is similar to triangle ABT. In triangle ACD and triangle ABT angle DAC = angle _________ (same angle) angle CDA = angle _________ (.........................................................) angle ACD = angle _________ (two angles in a triangle are equal, so the third angles are equal) Because the three pairs of angles are equal, the triangles are similar.[2]
  2. (b)Given that the radii of the circles are 7 cm and 3 cm, calculate CD.[3]

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Mark scheme

Marking points from the official mark scheme (Oct/Nov 2016). The mark or mark type is shown in brackets.

  1. [2] TAB, ATB Statement mentions tangent and radius, ABT
  2. [1] B1 for 2 pairs of equal angles.
  3. [3] 2.1
  4. [1] M1 for AC/AB = CD/BT oe soi and
  5. [1] M1 for 7/10 = CD/3 oe OR
  6. [1] B1 for (AB =) 10

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About this question

Topic
Geometry, O-Level Mathematics (syllabus 4024). Structured question, 5 marks.
Source
O-Level Mathematics, Oct/Nov 2016 Paper 2 Variant 2, question 5.

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