In the diagram, A and B are the centres of two circles that touch at P. The line ACT touches the small circle at T and intersects the large circle at C. D is the point on AB such that CDA = 90°. [Figure showing two touching circles, line ACT, point D on AB]
- (a)Complete the following, to show that triangle ACD is similar to triangle ABT. In triangle ACD and triangle ABT angle DAC = angle _________ (same angle) angle CDA = angle _________ (.........................................................) angle ACD = angle _________ (two angles in a triangle are equal, so the third angles are equal) Because the three pairs of angles are equal, the triangles are similar.[2]
- (b)Given that the radii of the circles are 7 cm and 3 cm, calculate CD.[3]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2016). The mark or mark type is shown in brackets.
- [2] TAB, ATB Statement mentions tangent and radius, ABT
- [1] B1 for 2 pairs of equal angles.
- [3] 2.1
- [1] M1 for AC/AB = CD/BT oe soi and
- [1] M1 for 7/10 = CD/3 oe OR
- [1] B1 for (AB =) 10
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