In the framework ABCD, BD = 3m. BDA = 27°, BCD = 41°. DBC and DÂB are right angles. [Figure showing a quadrilateral ABCD with given angles and side length BD=3]
- (a)(i)Find AD.[2]
- (a)(ii)Find CD.[3]
- (b)In triangle PQR, PQ = 3 m and QR = 5 m. The area of triangle PQR = 6m². Find the two possible values of PQR.[3]
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Mark scheme
Marking points from the official mark scheme (Oct/Nov 2016). The mark or mark type is shown in brackets.
- [2] 2.67
- [1] M1 AD/3 = cos 27 oe
- [3] 4.57
- [2] M2 for CD = 3/sin 41 oe or
- [1] M1 for 3/CD = sin 41 oe
- [3] 53.1 and 126.9
- [1] M1 for 1/2 × 3 × 5 × sin PQR = 6 oe and
- [1] A1 for 53.1 or
- [1] SC1 for supplementary angles from sin PQR = k.
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