Simplify (3a² / 10bc) ÷ (9a / 5b²c) .
- (a)Simplify (3a² / 10bc) ÷ (9a / 5b²c) .[2]
- (b)Simplify (h-k) / (5h-5k) .[2]
- (c)Factorise 9m² - 4n² .[1]
- (d)Factorise q (p - 2) + 3(2 – p) .[2]
- (e)(i)Find the two solutions of 5x-1=±9.[2]
- (e)(ii)The solutions of 5x-1=±9 are also the solutions of 5x² + Bx + C = 0, where B and C are integers. Find B and C.[2]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2016). The mark or mark type is shown in brackets.
- [2] ab/6 Final answer
- [1] M1 for correct transition to multiplication soi
- [2] 1/5 oe
- [1] B1 for 5(h-k)
- [1] (3m-2n)(3m + 2n) Final ans.
- [2] (p-2)(q-3) oe
- [1] B1 for -q(2-p) or -3(p-2) seen or
- [1] M1 if brackets removed and rearranged and extraction of p or 2 or for a correct extraction of a common factor after a sign error.
- [2] 2 and 8/5 oe
- [1] B1 for one correct or
- [1] B1 for either or
- [2] -2 and -16 cao
- [1] M1 for (5x−1)² = 9² or
- [1] (x-2)(x+8/5) = 0 oe ft or
- [1] Uses e(i) to form simultaneous equations or
- [1] (1±9) / (5*2) (from -B±√(B²-4AC))/(2A) )
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